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| fibb_par.append(fibb1) | ||
| for fibb in range(2, m): | ||
| fibb1, fibb2 = fibb2, fibb1 + fibb2 | ||
| if fibb >= n: |
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по условию имелось ввиду что n - это индекс элкмента в ряду
| # Напишите собственную реализацию стандартной функции filter. | ||
| # Разумеется, внутри нельзя использовать саму функцию filter. | ||
| def func(x): | ||
| return res_func |
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что-то мне подсказывает что тут программа упадет
| result_list = [] | ||
| for i in range(len(par2)): | ||
| if func(x) == true: | ||
| result_list.append(res_func) |
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хм, кажется функция filter возвращает список элементов, а не список с функциями...
| def filter_clone(res_func, par2): | ||
| result_list = [] | ||
| for i in range(len(par2)): | ||
| if func(x) == true: |
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Не совсем смог разобраться с заданием 3 части normal